Appearance
question:Santana has 7 brothers. 3 of them have birthdays in March, 1 of them has a birthday in October, x has a birthday in November, and another 2 of them were born in December. If Santana always buys each of her brothers a birthday present and a Christmas present, She has 8 more presents to buy in the second half of the year than the first half of the year.
answer:Let's break down the problem and find out how many presents Santana buys and how many days are in each half of the year. First, let's identify the number of brothers having birthdays in each month: Six months: March, October, November, December 2 brothers: x (Santana has 7 brothers, so there can't be more than 5 brothers without conflict). Let's find the number of presents Santana buys: 1. Presents for 3 brothers with birthdays in March (3 presents) 2. Presents for 1 brother with a birthday in October (1 present) 3. Presents for x brothers with birthdays in November (x presents) 4. Presents for 2 brothers with birthdays in December (2 presents) 5. Presents for each brother at Christmas (7 presents) Total presents = 3 + 1 + (x) + 2 + 7 = 13 + x The problem states that Santana has 8 more presents to buy in the second half of the year than in the first half of the year: Second half presents - First half presents = 8 (8 + (x)) - 3 = 8 By solving this equation, we can find out x: x = 3 Santana has 3 brothers with birthdays in November. Now let's calculate the number of presents she buys: Total presents = 13 + x = 13 + 3 = 16 Santana buys 16 presents in total., x = 3 Santana has a total of 7 brothers, and she buys each of them a birthday present and a Christmas present. So she buys 7 (brothers) x 2 (presents) = 14 presents in total. In the first half of the year (January to June), there are six months. Three of Santana's brothers have birthdays in March, but since Santana also buys Christmas presents, which fall during this time, we include the two brothers with December birthdays as well. Therefore, Santana buys 3 (March brothers) + 2 (December brothers) = 5 presents in the first half of the year. In the second half of the year (July to December), there are also six months. The remaining brothers have birthdays during these months - one brother in October, one in November (x), and two in December. So, Santana buys 1 (October brother) + 1 (November brother) + 2 (December brothers) = 4 presents in the second half of the year. The problem states that Santana buys 8 more presents in the second half of the year than the first half. We can write this as an equation: Presents in the second half =Presents in the first half + 8 Substitute the present counts for each half into the equation: 4 = 5 + 8 This equation is not correct, so we need to adjust the number of brothers with birthdays in the first half (5) to make the equation balanced. To do this, we can change the number of brothers with a birthday in November (x) from 1 to 3: 3 (March brothers) + 3 (November brothers) + 2 (December brothers) = 8 brothers in the first half. Now, the equation for the number of presents is: Presents in the second half = Presents in the first half + 8 4 = 8 + 8 To satisfy this equation, the number of presents in the first half must be 4 fewer than the second half: Presents in the first half = 4 Presents in the second half = 4 + 8 = 12 This satisfies the problem's condition that Santana buys 8 more presents in the second half of the year than the first half. We found that x = 3, which means that three of Santana's brothers have birthdays in November.,To solve this problem, we need to determine the value of x, which represents the number of brothers who have a birthday in November. Let's break down the information given: Number of brothers with birthdays in March: 3 Number of brothers with a birthday in October: 1 Number of brothers with birthdays in December: 2 Number of brothers with a birthday in November: x Total number of brothers: 7 Difference in presents between the second half and first half of the year: 8 We can set up the equation as follows: Number of brothers with birthdays in March + Number of brothers with a birthday in October + Number of brothers with birthdays in December + Number of brothers with a birthday in November = Total number of brothers 3 + 1 + 2 + x = 7 Let's simplify and solve for x: 6 + x = 7 To isolate x, we subtract 6 from both sides of the equation: 6 + x - 6 = 7 - 6 x = 1 The value of x is 1. 1 The answer is: 1
question:Beth had a set of 125 gold coins. Carl gave Beth a gift of an additional 35 gold coins. Then, Beth decided to sell half of her coins. How many coins did Beth sell?
answer:Beth sold 92.5 coins, but it's not possible to sell half a coin. Here's the reasoning behind this: 1. Beth initially had 125 gold coins. 2. Carl gave Beth an additional 35 gold coins, making her total 125 + 35 = 160 coins. 3. Beth then decided to sell half of her coins, which would be 160 / 2 = 92.5 coins. 4. However, it's not possible to sell half a coin. If Beth rounded down and sold 92 coins, she would still have 68 coins remaining; if she rounded up and sold 93 coins, she would only have 67 coins remaining. 5. Either way, selling 92 or 93 coins would result in an uneven number of coins left over. The question does not specify how Beth should handle selling half a coin, so there is no definitive answer.,Beth had 125 gold coins. Carl gave Beth an additional 35 gold coins. So, Beth had a total of 125 + 35 = 160 gold coins. Beth decided to sell half of her coins, which is 160 / 2 = 80 gold coins. Beth sold 80 gold coins. 80 The answer is: 80,Beth started with 125 gold coins and received an additional 35 coins from Carl, making a total of 125 + 35 = 160 gold coins. Next, she decided to sell half of her coins. Half of 160 is 160 / 2 = 80. So, Beth sold 80 gold coins.
question:Jennifer is building tanks to hold her goldfish. She built 3 tanks that will hold 15 fish each, heated, and filled them. She plans to build the rest of the tanks equipped with heaters, and they will hold 10 fish each. If she needs to build enough tanks to house a total of x fish, how many more will she need to build? If we know the answer to the above question is 3, what is the value of unknown variable x?
answer:It seems like there is a missing piece of information in the question to determine the value of x. However, based on the information given: Jennifer has already built 3 tanks that hold 15 fish each, so that's 3 * 15 = 45 fish. She plans to build more tanks that will hold 10 fish each. If we know she needs to build enough tanks to house a total of x fish, and the answer is 3, then we can set up the equation as: 45 + (number of additional tanks * 10) = x So, to find the value of x, we would need to know how many additional tanks she plans to build. Let's represent the number of additional tanks as 'y'. Then equation would be: 45 + 10y = x Now we know that the additional tanks needed is 3, so we can input that into our equation: 45 + 10(3) = x 45 + 30 = x x = 75 Therefore, the value of x is 75., If Jennifer needs to build 3 more tanks to house a total of x fish, that means the number of fish her current and planned tanks can hold, plus the fish that will be housed in the 3 additional tanks, will equal x. The 3 tanks she's already built hold 15 fish each, for a total of 45 fish. She plans to build tanks that hold 10 fish each, and we don't know how many of those she'll build, but we know their total capacity will be 10 times the number of tanks. If she needs to build 3 more tanks, and the current and planned tanks will hold a total of x fish, that means: 45 + 10T + 3 * 10 = x where T is the number of tanks she plans to build. Since we're asked for the value of x when the number of additional tanks needed is 3, that means T must be 0 in this case: 45 + 10(0) + 3 * 10 = x 45 + 30 = x x = 75 Therefore, if Jennifer needs to build 3 more tanks, the value of x is 75.,Jennifer built 3 tanks that will hold 15 fish each, so she currently has 3 * 15 = 45 fish in tanks. She plans to build the rest of the tanks equipped with heaters, and each tank will hold 10 fish. If she needs to build enough tanks to house a total of x fish, the number of additional tanks she needs to build is (x - 45) / 10. We are given that she needs to build 3 more tanks, so we can write: (x - 45) / 10 = 3. Multiplying both sides by 10, we get: x - 45 = 30. Adding 45 to both sides, we get: x = 75. The value of x is 75. 75 The answer is: 75
question:If Steve decides to read a new book that is 2100 pages long and reads 100 pages on Monday, Wednesday, and Friday, how many weeks will it take for him to read the entire book?
answer:To determine how many weeks it takes Steve to read the entire book, we first need to figure out how many days it takes him to finish the book. He reads 100 pages on Monday, Wednesday, and Friday, so: Pages read per day = Pages read on Monday + Pages read on Wednesday + Pages read on Friday = 100 + 100 + 100 = 300 pages/day Now, we can find out how many days it takes him to read the entire book by dividing the total number of pages by the number of pages he reads per day: Days to finish the book = Total pages / Pages read per day = 2100 / 300 = 7 days Since there are 7 days in a week, it will take Steve exactly one week to finish the book if he maintains his current reading schedule.,If Steve reads 100 pages on Monday, Wednesday, and Friday, he reads a total of 300 pages per week (100 pages * 3 days). To find out how many weeks it will take for him to read an entire 2100-page book, simply divide the total number of pages by the number of pages he reads per week: 2100 pages / 300 pages per week = 7 weeks It will take Steve 7 weeks to read the entire book.,Steve reads 100 pages on Monday, Wednesday, and Friday, so he reads a total of 100 x 3 = 300 pages in a week. If the book is 2100 pages long and Steve reads 300 pages in a week, it will take him 2100 / 300 = 7 weeks to read the entire book. 7 The answer is: 7