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question:I am trying to set a hook in my code using Detours, but I'm facing an issue. When I use the following code as the hook, it doesn't set the hook correctly. Instead, in the memory at 0x152942C6, I see a "jmp 00000000" instruction: ```c void tompa_sendto() { char buffer = {'x', 'y', 'z'}; return originalFunction(); } ``` Additionally, any code I place in `tompa_sendto()` crashes the program due to the bad jump instruction. The only two codes that I've managed to put there without crashing are `printf` and `messageBoxA`. Can anyone help me understand what's going wrong and how to fix it?

answer:It seems that you have not properly set up the trampoline for your hook function using Detours. A trampoline is a piece of memory that stores the original code of the function you are hooking and jumps to your hook function when the original function is called. If you don't properly set up the trampoline, you may end up with an incorrect jump instruction, as you've observed. Here's a general outline of how you can set up a hook using Detours: 1. Allocate memory for the trampoline. 2. Back up the original code of the function you want to hook in the trampoline. 3. Write your hook function at the target address where the original function resides. 4. Write a jump instruction in the trampoline to jump to your hook function. Here's an example of how you can set up the hook for `sendto` using Detours: ```c #include <windows.h> #include <detours.h> typedef int (WINAPI* sendto_t)(SOCKET s, const char* buf, int len, int flags, const struct sockaddr* to, int tolen); sendto_t originalFunction; void tompa_sendto() { char buffer = {'x', 'y', 'z'}; int sent = 3; // Length of the buffer int tolen = sizeof(struct sockaddr_in); // Length of the sockaddr_in structure // You can replace the following line with your custom implementation sendto_t originalFunction = (sendto_t)DetourFunction((PBYTE)originalFunction, (PBYTE)tompa_sendto); originalFunction(s, buffer, sent, 0, (struct sockaddr*)&to, tolen); DetourTransactionBegin(); DetourUpdateThread((HANDLE)_gettid()); DetourDetach(&(PVOID&)originalFunction, tompa_sendto); DetourTransactionCommit(); } extern "C" DECLDIR int WINAPI SendTo(SOCKET s, const char* buf, int len, int flags, const struct sockaddr* to, int tolen) { DetourTransactionBegin(); DetourUpdateThread((HANDLE)_gettid()); originalFunction = (sendto_t)DetourFunction((PBYTE)originalFunction, (PBYTE)tompa_sendto); DetourTransactionCommit(); return tompa_sendto(s, buf, len, flags, to, tolen); } ``` Compile this code with the Detours library and load it as a DLL. This should properly set up the trampoline and ensure that your `tompa_sendto` function is executed instead of the original `sendto` function. However, be aware that using Detours to hook low-level system functions can have unintended consequences and can cause the system to become unstable.,I was able to reproduce the problem and found a solution. The issue lies in the fact that your detour function is empty, causing a specific optimization by the compiler. When you return from another function, the compiler optimizes the call by jumping directly instead of calling, which means it doesn't push a return address. As a result, when the next function returns, it uses the previous function's return address, causing both functions to return at the same time. In your case, the function ends with `jmp func` instead of `call func; ret`. Furthermore, you are calling the original function through a variable, which results in an indirect jump. Detours 1.5 specifically checks if your function starts with an indirect jump. If it does, Detours hooks the target function with a direct jump based on the indirect jump it found. This is done to optimize the hooking process for functions called through indirect jump tables, such as DLL calls. In your specific case, since the `originalFunction` variable is 0 when you install the hook, the target function is hooked with a jump to address 0, resulting in the `jmp 00000000` instruction. To fix this issue, you can set the `originalFunction` variable to a non-zero value before installing the hook. For example, setting it to 3 should work. Alternatively, you can add a simple instruction, such as `__nop();`, before returning from the `tompa_sendto()` function. This will ensure that the function is not empty and will prevent the optimization that causes the bad jump instruction. By implementing either of these solutions, you should be able to set the hook correctly without encountering any crashes or incorrect jump instructions.,The problem you're facing might be due to memory protection settings on the page where the `originalFunction` is located. By default, Windows sets executable pages so that they can be executed in ring 3 only. When setting hooks with Detours, you need to adjust memory protection so the page can be executed from ring 0. To do this, you need to use `VirtualProtectEx()` to change the page's memory protection. Here is an example: ```c DWORD oldProtect; BOOL result = VirtualProtectEx(GetCurrentProcess(), &originalFunction, // Size of code 14, // PAGE_EXECUTE_READWRITE, &oldProtect); if (result) { // Display the previous and new protection flags. printf("Protecting 0x%p of size %d to PAGE_EXECUTE_READWRITEn", originalFunction, 14); printf("Previous: 0x%pnNew: 0x%pn", oldProtect, oldProtect); // Create your hook. } else { printf("Could not set memory protection for hookn"); } ``` Note: Replace `0x%p` with the correct address of `originalFunction` and `14` with the actual size of the function. After adding this code before setting the hook, you should be able to set the hook without any issues. Remember to restore the memory protection to its original state after the hook is in place by using `VirtualProtectEx()` with the PAGE_EXECUTE_READWRITE flag and the original protection value.

question:I'm trying to delete a record using the `destroy` method in Rails, but it's returning `false`. How can I find out why the record wasn't deleted? My model has two validations, both of which trigger on create only. Additionally, there is a callback, but it doesn't block if it fails. I don't have any traceback or error messages to look at. Can someone help me troubleshoot this? ```ruby person = Person.find(4123) person.destroy #=> false ```

answer:The reason why the `destroy` method is returning `false` is that the model is not actually being deleted from the database. It could be due to any of the following scenarios: 1. The attempt to destroy the model fails because of database integrity constraints. It is possible that the model or one of its related models have a validation which is failing during the deletion process. 2. There may be a foreign key constraint preventing the deletion. For example, if the model has a foreign key relation to another model, the record cannot be deleted if there are other records in the database which reference that model. 3. If you are using soft deletes (i.e., instead of deleting the record, you are just marking it as deleted), the `destroy` method will return `false` if the soft-delete process fails. To troubleshoot this, you can try the following steps: 1. Make sure you don't have a validation that is being triggered in the `destroy` method. As you've mentioned that both validations trigger on create only, but you haven't shared your code, I can't be certain. If you have a validation that is failing in `destroy`, it could cause the method to return `false`. 2. Check if there's any orphaned relationship. Like if there's a foreign key reference from another model to this model. You would have to clear all such references before deleting this model. 3. If you are using soft-deletes, check if your soft delete mechanism is correctly working. You'd have to check if the soft delete column is being updated correctly. 4. Try checking the database, if the record is being deleted or not. You may be able to see the actual SQL query being called when you try to destroy the model. If none of these seem to help, you may want to add some printing statements in your code or raise an exception if the record can't be deleted so that you have more information when something goes wrong.,I encountered a similar error recently, where the `destroy` method was returning `false` without any traceback or error messages. In my case, the issue was a logic error rather than a syntax or database-related problem. Upon investigation, I discovered that my models had conflicting `dependent: destroy` declarations in their relations. This meant that one model was attempting to delete a parent model that had already been deleted beforehand. To provide a clear example, let's consider the following model declarations: ```ruby class Section < ApplicationRecord has_many :contents, dependent: :destroy end class Content < ApplicationRecord belongs_to :section has_many :quizzes, dependent: :destroy end class Quiz < ApplicationRecord belongs_to :content, dependent: :destroy end ``` In my case, I attempted to delete a `Section` instance using `section.destroy`, which resulted in the error. The root cause was the `dependent: destroy` declaration in the `Quiz` model's relation to `Content`. Since the content was already deleted by the `dependent: destroy` in the `Section` model, the attempt to delete it again in the `Quiz` model caused the error. I hope this explanation helps you identify and resolve the problem in your code., If the `destroy` method is returning false, it usually means that there were associated records that could not be destroyed, likely due to foreign key constraints. To find out which associated records are causing the issue, you can check the `person.destroyed_records` association which will return an array of the destroyed associated records. You can then inspect each record to see why it couldn't be destroyed. Here's an example: ```ruby person = Person.find(4123) if person.destroy # record was successfully destroyed else # there were associated records that could not be destroyed associated_records = person.destroyed_records associated_records.each do |record| puts "Could not destroy #{record.class}: #{record.errors.full_messages.join(', ')}" end end ``` You can also check if there are any before_destroy callbacks defined in the `Person` model or any of its associated models that might be blocking the destruction of the record. Finally, if none of the above helps, you can check the Rails logs to see if there are any relevant messages or errors related to the destruction of the record. The logs are typically located in the `log` directory of your Rails application.

question:Is there a way to disable the .:format options in rails routes? I only want to use html format.

answer:Yes, you can disable the format options in Rails routes to only accept HTML format. You can do this by specifying the `:format` option with a value of `:html` in your route definition. Here's an example: ```ruby Rails.application.routes.draw do resources :books, only: :index, :show, format: :html end ,Yes, you can disable the other formats that Rails engine provides, including JSON, JS, XML, etc. to only use HTML format. Here's how you can do it: 1. Your application is using a config/initializers/routes.rb file where you can define the formats you want to support. Open that file. 2. Add the following code in the routes.rb file: ```ruby constraints(format: :html) do # Your routes here end ``` This code adds a constraint that limits your routes to only accept requests made with HTML format. Now your Rails app will recognize and serve HTML-only responses. Remember, from now on, your Rails application will only handle HTML format, ignoring other formats. Just make sure to remove this code or add other formats if needed in the future.,Yes, in Rails 3.1.1 and later versions, you can disable the .:format options in routes by adding `:format => false` at the end of the route declaration. This allows you to specify that you only want to use the HTML format. You can find more information about this in the Rails Routing Guide under the section 3.11 "Route Globbing", which can be accessed here(http://guides.rubyonrails.org/routing.html#request-based-constraints). For example, you can define a route like this: ```ruby match '*pages' => 'pages#show', :format => false ``` With this configuration, the `params:pages` will be able to include a period, as the format option is disabled. I hope this helps! Let me know if you have any further questions.

question:I am trying to create a boot program for RISC-V based boards by following a guide and adapting it for RISC-V. I am having trouble understanding a specific instruction in the guide. The instruction is "times 510 - ( - ) db 0". I tried filling the lines with ".8byte 0", but it doesn't seem feasible. Can someone explain what this instruction does and provide a better solution? ```assembly # # Boot Init # # .section .text start: nop j start .section .rodata .4byte 0 .8byte 0 .8byte 0 # repeat 60ish times .8byte 0x0000000000aa55 ``` Edit: I am using the gcc toolchain for RISC-V and the .rept directive. Here is my updated code: ```assembly # # Boot Init # # start: nop j start .section .rodata .rept 63 .8byte 0 .endr .4byte 0 .8byte 0 .8byte 0 .8byte 0x0000000000aa55 ``` The hex dump of the code is as follows: ``` 00000000 01 00 fd bf 00 00 00 00 00 00 00 00 00 00 00 00 00000010 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 * 00000210 55 aa 00 00 00 00 00 00 00000218 ``` I realized that I messed up the endianness of the code. However, I have a new question. What is the significance of the left column in the hex dump? The lines go from 0 to 10, then from 210 to 218. Also, why is there a blank line at 218? Edit: I realized that the left column in the hex dump represents the hexadecimal memory address. The asterisk (*) indicates that the memory is filled with zeros. The line numbering is in hexadecimal. Now, my final question is how to indicate to the board that the program is a boot program. Is there a specific magic number or any indication in the documentation of the board?

answer:To indicate that your program is a boot program for the RISC-V board, you need to follow the specifications provided by the board manufacturer. In the case of the HiFive1 board, the documentation states that the board is shipped with a modifiable boot loader at the beginning of SPI Flash (0x20000000). At the end of your boot program's execution, the core should jump to the main user portion of the code at a specific address, such as 0x20400000 for the original board or 0x20010000 for the rev b board. Based on the code you provided, it seems like you are targeting the rev b board. To create a boot program, you can use the following code: ```assembly # # Boot Init # # start: nop j start .section .rodata .rept 63 .8byte 0 .endr .4byte 0 .8byte 0 .8byte 0 .8byte 0x0000000000aa55 ``` This code fills the memory with zeros up until the last few bytes and ends with the universal boot indicator 0x0000000000aa55. Make sure to adjust the memory addresses and jump instructions according to the specifications of your board. Regarding the hex dump, the left column represents the hexadecimal memory address. The asterisk (*) indicates that the memory is filled with zeros. The blank line at 218 indicates the end of the memory dump. To properly indicate that your program is a boot program, refer to the documentation provided by the board manufacturer. They should specify the necessary magic number or other requirements for boot program identification., The instruction `times 510 - ( - ) db 0` is a way to initialize a buffer with 510 bytes of value 0 in NASM assembly syntax for x86 architecture. Here's how it works: * `times` is a directive that repeats the next instruction a certain number of times. * `510` is the number of times to repeat the following instruction. * `- ( - )` calculates the number of bytes already occupied by the previous instructions in the current section (`.rodata` in this case) and subtracts it from the current address () to get the final address. The difference is then used as the argument to the `times` directive. * `db 0` initializes one byte with the value 0. In your RISC-V assembly code, you can achieve the same effect using the `.rept` directive, which repeats a block of instructions a certain number of times. Here's a corrected version of your updated code: ```assembly .section .rodata .rept 510 .byte 0 .endr .section .text start: nop j start .4byte 0 .8byte 0 .8byte 0 .8byte 0x0000000000aa55 ``` Regarding your new question, the left column in the hex dump represents the hexadecimal memory address where each byte of data is stored in memory. The `*` character indicates that the same sequence of bytes is repeated several times. Regarding the final question, the way to indicate to the board that the program is a boot program depends on the specific board and the bootloader used. Some boards use a special prefix or a magic value to identify the beginning of the boot program, such as `0x37f` for the Xilinx Zynq-7000 series. Others may require a specific entry point address or an expected signature in the vector table. You should consult the documentation for your specific board for more information.,The "times 510 - ( - ) db 0" instruction in your guide is a directive in assembly language. It is not specific to RISC-V or any particular processor architecture. This directive is used to generate a given number of bytes with a specific value. In your case, "times 510 - ( - ) db 0" is filling 510 bytes with the value 0 to create a bootloader or "floppy disk boot sector". For RISC-V, you can utilize the `.rept` directive, as you have done in your updated code. This directive allows you to repeat a block of code or data a specified number of times. Regarding the blank line at 0x218, the hex dump displays the memory contents of the loaded image. It is customary to terminate bootloaders with a double word signature, which is two words to assert that machine code is presented. As for ensuring that your program is recognized as a boot program, you can follow the industry standards and use a magic number or special bytes in specific locations. For RISC-V, you can refer to the RISC-V documentation or consult the specific board's documentation to determine if there are any indications for boot program recognition. I hope this helps clarify your questions. Let me know if you need further assistance!

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