answer:In Mariam's neighborhood, there are 40 houses on one side of the main road passing through the neighborhood and x times as many homes on the other side of the road. There are 160 homes in Mariam's neighborhood. To solve this problem, we need to find the value of x. Let's break down the information given: Number of houses on one side of the main road = 40 Number of houses on the other side of the main road = x * houses on one side of the main road (40x) Total number of houses in Mariam's neighborhood = houses on the first side of the main road + houses on the other side of the main road 160 = 40 + 40x To solve for x, we subtract 40 from both sides of the equation: 160 - 40 = 40x 120 = 40x Now, we divide both sides of the equation by 40: 120 / 40 = x 3 = x The value of x is 3., We are given that there are 40 houses on one side of the main road and an unknown number of houses on the other side which is x times the number of houses on the first side. The total number of houses in the neighborhood is 160. To find the value of x, we can set up an equation using the information provided: Number of houses on one side = 40 Number of houses on the other side = x * Number of houses on one side Total number of houses = Number of houses on one side + Number of houses on the other side 160 = 40 + x * 40 Now, subtract 40 from both sides: 120 = x * 40 Next, divide both sides by 40: 3 = x So, there are 3 times as many homes on the other side of the road as there are on the first side.,To solve this problem, we need to determine the value of x, which represents the number of times there are as many homes on the other side of the road compared to the first side. Let's break down the information given: Number of houses on one side of the road: 40 Number of houses on the other side of the road: 40 * x Total number of houses in the neighborhood: 160 We can set up the equation as follows: Number of houses on one side of the road + Number of houses on the other side of the road = Total number of houses in the neighborhood 40 + 40 * x = 160 Let's simplify and solve for x: 40 + 40x = 160 To isolate x, we subtract 40 from both sides of the equation: 40 + 40x - 40 = 160 - 40 40x = 120 To solve for x, we divide both sides of the equation by 40: x = 120 / 40 x = 3 The value of x is 3. 3 The answer is: 3

answer:Macy runs 3 miles per day, so after 6 days, she would have run 3 miles/day * 6 days = 18 miles. Her goal is to run a total of 24 miles per week, so she would have 24 miles - 18 miles = 6 miles left to run. 6 The answer is: 6, First, let's determine how many miles Macy has already run after 6 days. We know that she runs 3 miles per day: Miles already run = Miles per day * Number of days = 3 * 6 = 18 miles Now, we'll subtract this amount from her weekly goal of 24 miles to find out how many more miles she needs to run: Miles remaining = Total goal - Miles already run = 24 - 18 = 6 miles So, Macy needs to run 6 more miles to meet her goal of 24 miles for the week.,Macy runs 3 miles per day, so after 6 days, she would have run 3 miles/day * 6 days = 18 miles. Her goal is to run a total of 24 miles per week, so she still has 24 miles - 18 miles = 6 miles left to run in order to meet her goal.

answer:Josie counted 80 antelopes. She counted 34 more rabbits than antelopes, so she counted 80 + 34 = 114 rabbits. The combined number of antelopes and rabbits is 80 + 114 = 194. She counted 42 fewer hyenas than the combined number of antelopes and rabbits, so she counted 194 - 42 = 152 hyenas. She counted 50 more wild dogs than hyenas, so she counted 152 + 50 = 202 wild dogs. The number of leopards was half the number of rabbits, so she counted 114 / 2 = 57 leopards. The total number of animals that Josie counted is 80 + 114 + 152 + 202 + 57 = 605. 605 The answer is: 605, Let's break down the problem step-by-step: 1. Josie counted 80 antelopes. 2. She counted 34 more rabbits than antelopes, so she saw 80 + 34 = 114 rabbits. 3. There were 42 fewer hyenas than the combined number of antelopes and rabbits, which is: 80 (antelopes) + 114 (rabbits) - 42 = 152 hyenas. 4. Josie also counted 50 more wild dogs than hyenas, so she saw 152 (hyenas) + 50 = 202 wild dogs. 5. Finally, the number of leopards was half the number of rabbits, so Josie saw 114 (rabbits) / 2 = 57 leopards. Now, let's add up all the animals Josie counted: 80 (antelopes) + 114 (rabbits) + 152 (hyenas) + 202 (wild dogs) + 57 (leopards) This gives us a total of 505 animals that Josie counted on her safari.,Let's start by finding the number of each animal Josie counted on her safari: - Antelopes: 80 - Rabbits: 80 (antelopes) + 34 = 114 - Hyenas: 80 (antelopes) + 114 (rabbits) - 42 = 152 - Wild dogs: 152 (hyenas) + 50 = 202 - Leopards: 114 (rabbits) / 2 = 57 Now let's find the total number of animals Josie counted by adding all these numbers together: Total animals: 80 (antelopes) + 114 (rabbits) + 152 (hyenas) + 202 (wild dogs) + 57 (leopards) = 505 animals.

answer:First, let's find out how many classrooms have 30 desks: Classrooms with 30 desks = Total classrooms / 3 = 15 / 3 = 5 Since there are 10 classrooms left and they all have 25 desks, we can calculate the maximum number of students these classrooms can accommodate by multiplying the number of classrooms by the number of desks in each: Students in 25-desk classrooms = Number of classrooms * Desks per classroom = 10 * 25 = 250 Now, we need to calculate the number of students that the classrooms with 30 desks can accommodate: Students in 30-desk classrooms = Number of classrooms * Desks per classroom = 5 * 30 = 150 Finally, we add the number of students from both types of classrooms to get the maximum number of students the school can accommodate: Total students = Students in 25-desk classrooms + Students in 30-desk classrooms = 250 + 150 = 400 So, the school can accommodate a maximum of 400 students while ensuring that each student has their own desk.,One-third of the classrooms have 30 desks, so there are 15/3 = 5 classrooms with 30 desks. The other two-thirds of the classrooms have 25 desks, so there are 15 - 5 = 10 classrooms with 25 desks. In the classrooms with 30 desks, there can be a maximum of 5 classrooms x 30 desks = 150 students. In the classrooms with 25 desks, there can be a maximum of 10 classrooms x 25 desks = 250 students. Therefore, the maximum number of students the school can accommodate is 150 + 250 = 400 students. 400 The answer is: 400,Let's consider the number of desks in each type of classroom: 1. There are 1/3 * 15 = 5 classrooms with 30 desks each. 2. The remaining 2/3 * 15 = 10 classrooms have 25 desks each. Next, we calculate the total number of desks: 1. In the classrooms with 30 desks: 5 classrooms * 30 desks/class = 150 desks. 2. In the classrooms with 25 desks: 10 classrooms * 25 desks/class = 250 desks. Now, add both types of desks to find the total available desks: Total Desks = Desks with 30/class + Desks with 25/class Total Desks = 150 + 250 = 400 desks Since only one student can sit at each desk, the maximum number of students the school can accommodate is the same as the total available desks: 400 students.