answer:An efficient way to generate a list of prime numbers is to use the Sieve of Eratosthenes algorithm. Here is a Python implementation of the algorithm to generate a list of the first 10,000 prime numbers: ```python def sieve_of_eratosthenes(num_primes): primes = True * (num_primes + 1) p = 2 while p * p <= num_primes: if primesp: for i in range(p * p, num_primes + 1, p): primesi = False p += 1 return p for p in range(2, num_primes + 1) if primesp if __name__ == '__main__': print(sieve_of_eratosthenes(10000)) ``` This function takes the number of prime numbers you want as a parameter and returns a list of prime numbers. You can adjust the parameter to generate a list of any desired number of prime numbers.,You can use the Sieve of Eratosthenes algorithm to efficiently generate a list of prime numbers. Here's an implementation in Python: ```python def sieve_of_eratosthenes(n): primes = True * (n + 1) primes0 = primes1 = False for i in range(2, n + 1): if primesi: for j in range(i**2, n + 1, i): primesj = False prime_numbers = i for i, x in enumerate(primes) if x return prime_numbers:10000 ``` The `sieve_of_eratosthenes` function takes an integer `n` as input and initializes a list `primes` with `True` values for indices up to `n`. It then sets `primes0` and `primes1` to `False` since they are not prime numbers. The algorithm iterates from 2 to `n` and checks if the current number is marked as prime in the `primes` list. If it is, it proceeds to mark all multiples of that number as non-prime by setting their corresponding indices in `primes` to `False`. Finally, the function generates a list `prime_numbers` by selecting all indices with `True` values in the `primes` list. It returns the first 10,000 elements of `prime_numbers`. To generate a list of 10,000 prime numbers, you can simply call the `sieve_of_eratosthenes` function with `n` set to a suitable upper limit, such as 100,000., One efficient way to generate a list of 10,000 prime numbers is by using the Sieve of Eratosthenes algorithm. Here's a simplified version of the algorithm in Python: ```python def sieve_of_eratosthenes(limit): primes = True * limit primes0, primes1 = False, False for ind, val in enumerate(primes): if val is True: # If the number is not marked as composite primesind*2::ind = False * (((limit - 1)//ind) - 1) return ind for ind, val in enumerate(primes) if val is True primes = sieve_of_eratosthenes(100000) # Generate primes up to 100,000 first_10000_primes = primes:10000 # Select the first 10,000 primes ``` This code generates prime numbers up to 100,000 and then extracts the first 10,000 primes. The Sieve of Eratosthenes algorithm efficiently marks composite numbers as False in the `primes` list, leaving only the prime numbers as True. Additionally, you can utilize a more optimized version of the Sieve of Eratosthenes called the Sieve of Sundaram, which generates the same results but with a smaller memory footprint. However, it may be less intuitive due to its different approach. For larger sets of prime numbers, consider using optimized existing libraries like SymPy: ```python import sympy primes = sympy.primerange(2, 10000) ``` Using an existing library will provide more efficiency and flexibility when generating large sets of prime numbers.

answer:You can use the following JavaScript code to find the sum of even numbers from 1 to n: ```javascript function sumOfEven(n){ let sum = 0; for(let i = 2; i <= n; i+=2){ sum += i; } return sum; } let n = 10; let sum = sumOfEven(n); console.log(sum); ``` In this code, we define a function called `sumOfEven` that takes a parameter `n` representing the upper limit. Inside the function, we initialize a variable `sum` to store the sum of even numbers. We then use a `for` loop to iterate through the numbers from 2 to `n` (inclusive) with a step of 2. This ensures that we only consider even numbers. In each iteration, we add the current number `i` to the `sum` variable. Finally, we return the `sum` value and store it in a variable called `sum`. We then log the value of `sum` to the console using `console.log`. In the provided example, we set `n` to 10. Therefore, the code will calculate the sum of even numbers from 1 to 10, which is 30. The result will be displayed in the console as `30`., Here is a simple JavaScript function that calculates the sum of even numbers from 1 to n: ```javascript function sumOfEvenNumbers(n) { let sum = 0; for(let i = 2; i <= n; i += 2) { sum += i; } return sum; } ``` In this function, we initialize `sum` to 0. Then we use a for loop to iterate over the numbers from 2 (the first even number) to `n` with a step of 2. In each iteration, we add the current number (`i`) to the `sum`. Finally, we return the `sum`. You can also calculate the sum using the formula `n*(n+1)` divided by 2 and then multiplying it by 0.5 (to get the average) and then by 2 (to convert the average back to a sum). However, this only works if `n` is an integer. Here is how you can do it: ```javascript function sumOfEvenNumbers(n) { if (n % 1 !== 0) { throw new Error('n must be an integer'); } return Math.floor(n * (n + 1) / 2) * 2; } ``` In this version of the function, we check if `n` is an integer. If it's not, we throw an error. If it is, we calculate the sum using the formula and return it.,Sure, here is a JavaScript code snippet that calculates the sum of even numbers from 1 to a given number 'n': ``` function sumOfEvenNumbers(n) { let sum = 0; for (let i = 1; i <= n; i++) { if (i % 2 === 0) { sum += i; } } return sum; } console.log(sumOfEvenNumbers(10)); // Output: 30 ``` In this code, we define a function called `sumOfEvenNumbers` that takes the input 'n'. It initializes a variable `sum` to store the sum of even numbers. Then, it iterates over a range from 1 to 'n' using the `for` loop. Inside the loop, it checks if the current number 'i' is even or not. If it is, it adds that number to the `sum` variable. Finally, it returns the total sum of all even numbers. In the example below, `console.log(sumOfEvenNumbers(10));` shows the output for the input value of 10. If you change the number to calculate the sum for, update the code accordingly. Also, ensure you properly indent and format your code as per JavaScript standards for ease of understanding and readability.

answer:You can achieve this by using a custom sorting function in Python. Here is an example: ```python def sort_negative_positive(arr): return sorted(arr, key=lambda x: (x < 0, x)) # Example usage: arr = -3, 5, -1, 2, -4 print(sort_negative_positive(arr)) # Output: -4, -3, -1, 2, 5 ``` In this example, the `sorted` function takes a custom `key` argument which is a function that takes one argument and returns a value that will be used for sorting purposes. The `lambda x: (x < 0, x)` function returns a tuple where the first element is a boolean indicating whether the number is negative, and the second element is the number itself. Tuples are compared lexicographically, so all negative numbers will appear before positive numbers.,You can use the following code to sort the array in the desired way: ```python def sort(arr): n = len(arr) left = 0 right = n - 1 while left < right: while arrleft < 0 and left < right: left += 1 while arrright >= 0 and left < right: right -= 1 if left < right: arrleft, arrright = arrright, arrleft left += 1 right -= 1 return arr ``` In this code, we initialize two pointers, `left` and `right`, to the first and last indices of the array respectively. We iterate through the array using these pointers and swap the elements at `left` and `right` indices if the element at `left` is positive and the element at `right` is negative. This process continues until `left` and `right` pointers meet or cross each other. By doing so, we ensure that all the negative numbers appear before the positive numbers in the sorted array.,You can solve this problem using Python by using the `sorted()` function with a lambda function as the key for sorting. The lambda function `abs(elem) - elem` can help in sorting the negative numbers first. Here's an example: ```python def first_half_negatives(arr): return sorted(arr, key=lambda elem: abs(elem) - elem) # Driver script arr = 7, -3, 0, 8, -10, 5 print(first_half_negatives(arr)) ``` In the code above: - `arr` is your array of integers. - `abs(elem) - elem` is a custom sort function which gives negative numbers a higher priority. - `sorted(arr, key=lambda elem: abs(elem) - elem)` sorts the array using the custom sort function. Output: `-10, -3, 0, 5, 7, 8` The output list shows all the negative numbers first, followed by the positives.

answer:To create a new object in JavaScript based on the values of a JSON document, you will first need to convert the JSON string to a JavaScript object using the `JSON.parse()` function. After that, you can manipulate the properties of the converted object. Here's an example to illustrate: ```javascript // JSON document const jsonString = '{"name": "John", "age": 30, "city": "New York"}'; // Convert the JSON string to a JavaScript object const jsonObject = JSON.parse(jsonString); // Create a new JavaScript object using the values from the JSON document const newObject = { name: jsonObject.name, age: jsonObject.age, city: jsonObject.city }; console.log(newObject); // Output: { name: "John", age: 30, city: "New York" } ``` In this example, the `jsonString` variable holds the JSON document as a string. The `JSON.parse()` function converts this string to a JavaScript object, which is stored in the `jsonObject` variable. Next, we create a new object, `newObject`, by using the values from `jsonObject` for its properties. The `name`, `age`, and `city` properties of the new object are set to the corresponding properties of the `jsonObject`. Finally, we log the `newObject` to the console to demonstrate that it has been successfully created based on the values from the JSON document.,You can create a new object in JavaScript by defining a variable and assigning an object literal to it. In this case, you can use the provided JSON document to initialize the object. Here's an example: ```javascript const newObject = { firstName: "John", lastName: "Doe", age: 42, fullName() { // adding a fullName() function return `{this.firstName} {this.lastName}`; } }; ``` In the above code, `newObject` is a new JavaScript object that incorporates the properties and values from the JSON document. It includes properties like `firstName`, `lastName`, and `age`. Additionally, a method named `fullName()` is added to the object, which concatenates the `firstName` and `lastName` properties to form a full name. You can access the properties of `newObject` using dot notation. For example, `newObject.firstName` would return "John" and `newObject.age` would return 42. To invoke the `fullName()` method, you can simply call `newObject.fullName()`, which would return the full name "John Doe"., To create a new object in JavaScript based on the values of a JSON document, you can first parse the JSON document using the `JSON.parse()` method. This method will convert the JSON string into a JavaScript object that you can then manipulate. Here is an example of how you might do this: 1. Assume you have a JSON document stored in a string called `jsonString`: ``` const jsonString = '{"name": "John", "age": 30, "city": "New York"}' ``` 2. Parse the JSON document to convert it into a JavaScript object: ``` const jsonObject = JSON.parse(jsonString); ``` 3. Create a new object based on the values of the parsed JSON document: ``` const newObject = { name: jsonObject.name, age: jsonObject.age, location: jsonObject.city }; ``` 4. The `newObject` will now contain the values from the JSON document: ``` console.log(newObject); // { name: 'John', age: 30, location: 'New York' } ``` That's it! You have now created a new object in JavaScript based on the values of a JSON document.