Appearance
question:I have asynchronous code in Rust which calls synchronous code that takes a while to run. I followed the suggestions in this Stack Overflow post(https://stackoverflow.com/q/41932137/155423) to encapsulate the blocking I/O using `spawn_blocking` and `timeout` from the `tokio` library. However, even when the timeout fires, the synchronous code continues to run. How can I stop running the synchronous code when the future wrapping it is dropped? Here is my code: ```rust use std::{thread, time::Duration}; use tokio::{task, time}; // This takes 1 second fn long_running_complicated_calculation() -> i32 { let mut sum = 0; for i in 0..10 { thread::sleep(Duration::from_millis(100)); eprintln!("{}", i); sum += i; // Interruption point } sum } #tokio::main async fn main() { let handle = task::spawn_blocking(long_running_complicated_calculation); let guarded = time::timeout(Duration::from_millis(250), handle); match guarded.await { Ok(s) => panic!("Sum was calculated: {:?}", s), Err(_) => eprintln!("Sum timed out (expected)"), } } ``` The output of this code shows that the timeout fires, but the synchronous code also continues to run: ``` 0 1 Sum timed out (expected) 2 3 4 5 6 7 8 9 ``` I expect the synchronous code to stop running when the future is dropped. Is there a way to achieve this in Rust?
answer:In Rust, it is not currently possible to automatically stop the execution of synchronous code when the wrapping future is dropped. However, you can manually handle cancellation by using an atomic boolean flag. Here is a modified version of your code that stops the synchronous code when the future is dropped: ```rust use std::sync::atomic::{AtomicBool, Ordering}; use std::sync::Arc; use std::{thread, time::Duration}; use tokio::{task, time}; // This takes 1 second fn long_running_complicated_calculation(flag: &AtomicBool) -> i32 { let mut sum = 0; for i in 0..10 { thread::sleep(Duration::from_millis(100)); eprintln!("{}", i); sum += i; // Interruption point if !flag.load(Ordering::Relaxed) { eprintln!("Interrupted..."); break; } } sum } #tokio::main async fn main() { let some_bool = Arc::new(AtomicBool::new(true)); let some_bool_clone = some_bool.clone(); let handle = task::spawn_blocking(move || long_running_complicated_calculation(&some_bool_clone)); let guarded = time::timeout(Duration::from_millis(250), handle); match guarded.await { Ok(s) => panic!("Sum was calculated: {:?}", s), Err(_) => { eprintln!("Sum timed out (expected)"); some_bool.store(false, Ordering::Relaxed); } } } ``` In this code, we introduce an atomic boolean flag `some_bool` that indicates whether the synchronous code should continue running. This flag is initially set to `true`. Inside the `long_running_complicated_calculation` function, we check the flag after each iteration of the loop. If the flag is `false`, we break out of the loop and print "Interrupted...". In the `main` function, we create an `Arc` of the atomic boolean flag and pass a clone of it to the `long_running_complicated_calculation` function. After the `guarded.await` call, if the timeout occurs, we set the flag to `false` using `some_bool.store(false, Ordering::Relaxed)`. This will cause the synchronous code to stop running. Note that this approach requires manual handling of the cancellation flag. There are ongoing discussions and work in the Tokio library to improve automatic cancellation of futures, but it is not available in the current version.,In the provided code, we're not using the interruption point (`sync.CoordinatedQueue.release()` in the linked Stack Overflow post) correctly. Here's a modified version that should achieve the desired behavior: ```rust use std::time::Duration; use tokio::{task, time}; // Rest of the code is the same ``` The issue here is that we're not waiting for the result of the `release()` call to propagate and cause the synced block to stop executing. By using the `.with_executor(|executor|)` method, we ensure that the `release()` call is executed on the same thread as the task and allows the task to be aware of signal interrupting. This way, when we reach the `token.send(Release)` in our example, the task will be aware of the signal and decide to stop executing based on the timeout. Note If you can use `cancellation` or `parking_lot` crates, there are better ways to achieve the desired behavior., In Rust, there is no straightforward way to forcibly stop a synchronous function from running once it has started, especially when using `tokio::spawn_blocking`. The `spawn_blocking` function is designed to offload blocking work to a separate thread-pool provided by the Tokio runtime, and it does not provide a way to cancel the spawned task. Therefore, the synchronous code will continue to run even after the future is dropped. However, if you need to limit the execution time of the synchronous function, you can modify it to check for an interruption point and stop running if the interruption point is reached. In your example, you've already added an interruption point in the `long_running_complicated_calculation` function. You can make use of an `AtomicBool` to determine if the calculation should be interrupted. Here's the updated code: ```rust use std::{ sync::atomic::{AtomicBool, Ordering}, thread, time::Duration, }; use tokio::{task, time}; static INTERRUPTED: AtomicBool = AtomicBool::new(false); // This takes 1 second fn long_running_complicated_calculation() -> i32 { let mut sum = 0; for i in 0..10 { if INTERRUPTED.load(Ordering::Acquire) { break; } thread::sleep(Duration::from_millis(100)); eprintln!("{}", i); sum += i; } sum } #tokio::main async fn main() { let handle = task::spawn_blocking(move || { long_running_complicated_calculation(); INTERRUPTED.store(true, Ordering::Release); }); let guarded = time::timeout(Duration::from_millis(250), handle); match guarded.await { Ok(_) => panic!("Sum was calculated (unexpected)"), Err(_) => eprintln!("Sum timed out (expected)"), } // Stopping the calculation INTERRUPTED.store(true, Ordering::Release); } ``` In this example, the `INTERRUPTED` variable is an `AtomicBool`. The `long_running_complicated_calculation` function now periodically checks for an interruption. After starting the blocking task, the main function sets the `INTERRUPTED` variable to `true` after the timeout. While this doesn't forcibly stop the synchronous code, it does limit the execution time by using an interruption point. This approach may work for your use case, depending on the requirements and the details of the synchronous code you're trying to run. If you want to cancel the synchronous task more strictly, consider refactoring the code to use `tokio::task` instead of `tokio::spawn_blocking`. This way, you can have more control over the asynchronous task, and you can hook into the task cancellation flow provided by Tokio.
question:I have a simple function that I want to test. Here's the code: ```go func (t *Thing) print(min_verbosity int, message string) { if t.verbosity >= minv { fmt.Print(message) } } ``` But how can I test what the function actually sends to standard output? I found a Perl module called Test::Output that does what I want, but I'm looking for a similar solution in Go. I came across this code snippet on Stack Overflow, which sets up a pipe and redirects stdout to it: ```go orig = os.Stdout r,w,_ = os.Pipe() thing.print("Some message") var buf bytes.Buffer io.Copy(&buf, r) w.Close() os.Stdout = orig if(buf.String() != "Some message") { t.Error("Failure!") } ``` However, this seems like a lot of extra work for every single test. Is there a more standard way or an abstraction library that can handle this for me?
answer:One way to avoid writing the boilerplate code for every test is to create a helper function that captures the output of the function being tested. Here's an example of such a function: ```go func captureOutput(f func()) string { var buf bytes.Buffer log.SetOutput(&buf) f() log.SetOutput(os.Stderr) return buf.String() } ``` You can then use this function in your tests like this: ```go output := captureOutput(func() { // Call the print function here thing.print(2, "Some message") }) // Use an assertion library to check the output assert.Equal(t, "Some message", output) ``` In this example, we capture the output of the `print` function by temporarily redirecting the `log` output to a buffer. After calling the function, we restore the original output destination. Finally, we can use an assertion library like `testify/assert` to compare the captured output with the expected value., You're correct that the solution you found involves quite a bit of boilerplate code. For a more standard way in Go, you can use the "testing" package's `testing.T.CaptureStdout` and `testing.T.Cleanup` methods to simplify your test function. Here's an example, adapting your provided code snippet: ```go func TestThingPrint(t *testing.T) { orig := os.Stdout r, w, err := os.Pipe() if err != nil { t.Fatalf("Failed to create pipe: %v", err) } // Set stdout to 'w' for capturing output os.Stdout = w t.Run("Verify prints message", func(t *testing.T) { thing := &Thing{verbosity: 1, minv: 0} thing.print(0, "Some messagen") w.Close() var buf bytes.Buffer buf.ReadFrom(r) // Reset stdout os.Stdout = orig if buf.String() != "Some messagen" { t.Errorf("Failed to print 'Some message'. Actual: '%s'", buf.String()) } }) // Optionally, add more test cases inside the 't.Run' calls } ``` This way, you can centralize the pipe setup in a single test function, and use `t.Run` to create separate test cases for your function's behavior. There isn't a widely-used standard library for capturing output in Go, so this approach appears to be suitable for most use cases. However, if you prefer a third-party library, you can take a look at Jesseduffield/go-testing-interface, which appears to be suitable for capturing standard output in tests. By the way, you mentioned you found the answer in Perl. For future tasks like this, I recommend checking out the "GoDoc" website (https://pkg.go.dev/) to find potential methods in Go, even if you're unsure how tasks should be done in Go. It appears that Perl and Go have different libraries and features, so in most cases, it will be better to search for Go-specific libraries and features.,Yes, there is a simpler and more idiomatic approach in Go for testing functions that write to output. You don't need to open a pipe or redirect stdout every time. Instead, you can use the built-in `testing.T.Run()` function, which allows you to write assertions to test expected output compared to the actual output. Here's an example of how you can modify your test code: ```go import ( "bytes" "testing" ) func TestMyFunc(t *testing.T) { thing := &Thing{} // Simulate your function being called var buf bytes.Buffer os.Stdout = &buf thing.Print("Some message") // Assert that the function outputs the expected message if buf.String() != "Some message" { t.Error("Expected: 'Some message', but got:", buf.String()) } } type Thing struct {} func (t *Thing) Print(min_verbosity int, message string) { // This is the original function you want to test if t.Verbosity >= min_verbosity { fmt.Print(message) } } ``` In this code, you set `os.Stdout` to point to a `bytes.Buffer` instead of the actual output. This way, you can capture the output in the `buf` variable. Then, you can compare the `buf`'s contents with the expected output using an `if` statement and the `t.Error()` function. If the output is different than expected, an error will be reported. This approach is simpler, requires less code, and doesn't involve opening pipes or redirecting stdout for each test.
question:Why do certain combinations of CPU instructions in Masm not correctly detect coprocessor instructions that require a wait prefix?
answer:In Masm, certain combinations of CPU instructions do not correctly detect coprocessor instructions that require a wait prefix. This issue arises when using the following combinations: - Example 1: `.386` and `.8087` directives - Example 2: `.286` and `.8087` directives - Example 3: `.386` and `.287` directives When a math coprocessor instruction is used after these combinations, a wait prefix (which is normally created by MASM) will NOT be created. This means that instructions requiring a wait prefix will not have one when they should. The affected instructions include: FRSTOR, FFREE, FDECSTP, FINCSTP, FLDENV, FLDCW, FLD, FST, FSTP, FXCH, FLDZ, FLD1, FLDPI, FLDL2E, FLDL2T, FLDLG2, FLDLN2, FILD, FIST, FISTP, FBLD, FBSTP, FCOM, FCOMP, FCOMPP, FICOM, FICOMP, FXAM, FADD, FADDP, FMUL, FMULP, FSUB, FSUBP, FSUBR, FSUBRP, FDIV, FDIVP, FDIVR, FDIVRP, FABS, FCHS, FSQRT, FRNDINT, FIADD, FIMUL, FISUB, FISUBR, FIDIV, FIDIVR, FPTAN, FPATAN, F2XM1, FSCALE, FYL2X, FYL2XP1, FPREM, FPREM1, FXTRACT, FSETPM, and FNOP. However, there are some instructions that are not affected by this issue. These instructions include: FCLEX, FNCLEX, FSAVE, FNSAVE, FENI, FNENI, FDISI, FNDISI, FSTENV, FNSTENV, FINIT, FNINIT, FSTSW, FNSTSW, FSTCW, and FNSTCW. It is unclear whether this behavior is a bug or intended functionality, as there is no documentation mentioning it. The version of MASM being used is MASM v6., In MASM (Microsoft Macro Assembler), when writing assembly code that utilizes x87 floating-point coprocessor instructions, you might encounter situations where certain combinations of CPU instructions do not correctly detect and insert the wait prefix (`FWAIT` or `WAIT`) before coprocessor instructions that require it. This can lead to incorrect execution, timing issues, or even crashes. The x87 floating-point unit (FPU) is a component of the x86 CPU that handles floating-point arithmetic. Some FPU instructions take a long time to execute, and if the CPU executes another floating-point instruction before the previous one has completed, it might lead to a race condition known as "floating-point exception" or "NaN (Not a Number) propagation." To prevent this, the `FWAIT` or `WAIT` prefix can be used before a coprocessor instruction to ensure that the previous floating-point instruction has completed execution before the next one starts. MASM can automatically insert the wait prefix for you, but there are limitations to its capability. MASM uses a model called the "hardware interrupt 13h (INT 13h) model" or "protected mode model" for floating-point instructions. In this model, MASM checks the CPU capabilities, and if the CPU supports the `FWAIT` instruction, MASM will automatically insert it before coprocessor instructions that require it. However, this model has some limitations and might not work correctly in certain situations. 1. **Instruction combinations:** MASM might not detect the need for a wait prefix when there are multiple coprocessor instructions in a row. For example, consider the following code: ```asm fld dword ptr ebx fmul dword ptr ecx fld dword ptr edx faddp ``` MASM might not insert a wait prefix between the `fmul` and `fld` instructions because, according to the hardware interrupt 13h model, it does not expect a floating-point exception to occur. 2. **Code optimization:** Modern CPUs have advanced pipelining and out-of-order execution capabilities. MASM's protected mode model does not take these CPU features into account, and the wait prefix might not have the desired effect, as the CPU might still execute multiple floating-point instructions concurrently. To address this issue, you can manually insert the `FWAIT` or `WAIT` prefix before coprocessor instructions that require it, or use the `EMMS` instruction to ensure that the FPU is in a known state before and after using it. Alternatively, consider using SSE (Streaming SIMD Extensions) instructions, which have better support for concurrent execution and do not require wait prefixes or the `EMMS` instruction.,The failure to correctly detect coprocessor instructions that require a wait prefix in various combinations of CPU instructions in Masm can be attributed to certain factors. One of the most critical factors is the order in which the CPU executes instructions. This is known as instruction pipelining, which allows the CPU to perform multiple instructions at the same time. Moreover, the delay caused by the wait prefix is sometimes enough for the CPU to finish some instructions that contained an earlier wait. The CPU might then continue processing the next instruction without recognizing that the previous instruction required a wait. This could lead to incorrect results. Additionally, the CPU architecture and its optimization techniques can also influence the correctness of coprocessor instructions. Some CPUs, such as older versions or specific microarchitectures, might not support certain coprocessors or detection mechanisms properly. Due to these reasons, some combinations of CPU instructions in Masm may not correctly detect certain coprocessor instructions that require a wait prefix. It is necessary to understand these conditions and workarounds cautiously when dealing with these instructions.
question:I have inherited a Blazor Webassembly application and I noticed that some of the components use `await Task.Run(StateHasChanged)` instead of `await InvokeAsync(StateHasChanged)`. I am encountering an exception when trying to render the component using bUnit, specifically the exception states "System.InvalidOperationException: The current thread is not associated with the Dispatcher. Use InvokeAsync() to switch execution to the Dispatcher when triggering rendering or component state." I changed the code to `await InvokeAsync(StateHasChanged)` and now the component can be rendered in bUnit. However, I want to understand the difference between these two approaches to invoking `StateHasChanged`. Can someone explain?
answer:In Blazor, components are updated asynchronously on the UI thread through a message loop known as the rendering loop. This loop is responsible for handling various events, such as user input, timers, and navigation, and updating the UI accordingly. The `StateHasChanged` method is used to request a component to re-render itself. When you call `StateHasChanged`, it queues a message in the rendering loop to update the component. However, since `StateHasChanged` is not an asynchronous method, it must be called on the UI thread. In a Blazor WebAssembly application, the UI thread is the main thread of the JavaScript runtime that runs the application. When you execute code on this thread, it can modify the UI directly. However, when you execute code on a background thread, it cannot modify the UI directly. The `Task.Run` method schedules the execution of a delegate on a background thread. So when you call `await Task.Run(StateHasChanged)`, you are executing `StateHasChanged` on a background thread, which can result in the exception you are seeing. This is because the background thread is not associated with the rendering loop, and therefore cannot execute UI updates. On the other hand, the `InvokeAsync` method is used to execute a delegate on the UI thread. This ensures that the `StateHasChanged` method is called on the correct thread, and the rendering loop can update the UI as necessary. In summary, you should always use `InvokeAsync` to call `StateHasChanged` to ensure that it is executed on the UI thread, even when executing code asynchronously with `await`. Using `Task.Run` to execute `StateHasChanged` on a background thread can result in exceptions and unexpected behavior.,Yes, sure. In Blazor, the `StateHasChanged()` method is used to force a re-render of a component. This is typically done when the component's state has changed and the component needs to be updated. The `Task.Run()` method is a method in .NET, it runs the given delegate asynchronously on the ThreadPool and returns a task that represents that work. Now, when using `await Task.Run(StateHasChanged)`, this would cause Blazor to run StateHasChanged on a background thread, which might not be the thread Blazor is expecting to handle state changes. This is why you're seeing the exception. On the other hand, `InvokeAsync(StateHasChanged)` is the correct way to trigger rendering in a Blazor component because it ensures that the work is done on the correct thread, something that's important because Blazor (server and webassembly) uses a single-threaded render model. This means that it performs all rendering operations, such as component rendering, on a single thread. The `InvokeAsync()` method is another method from the `IJSRuntime` interface in Blazor, which is an instance of JavaScript interop. What 'InvokeAsync' does is it take the code and executes it, in our case the `StateHasChanged`. So when you change code from `await Task.Run(StateHasChanged)` to `await InvokeAsync(StateHasChanged)`, you're actually making sure that the component update request is being handled on the correct thread which is critical for Blazor applications. In conclusion, the best practice when dealing with Blazor components and StateHasChanged is to use `InvokeAsync(StateHasChanged)`, especially when dealing with asynchronous operations where having the work executed on the correct thread is essential.,Certainly! The difference between `await Task.Run(StateHasChanged)` and `await InvokeAsync(StateHasChanged)` lies in how the `StateHasChanged` method is executed. In Blazor WebAssembly, there is only one main thread available to execute code. This means that any UI-related updates, such as calling the `StateHasChanged` method to trigger a re-render of the component, must be executed on this main thread. When you use `await Task.Run(StateHasChanged)`, the `StateHasChanged` method is executed on a separate thread from the main thread, known as the ThreadPool. However, since Blazor WebAssembly does not currently support multiple threads, this approach is incorrect and can lead to issues like the exception you encountered. On the other hand, when you use `await InvokeAsync(StateHasChanged)`, the `StateHasChanged` method is executed on the main thread. The `InvokeAsync` method ensures that the provided delegate (in this case, `StateHasChanged`) is executed synchronously on the main thread, allowing for safe UI updates. To summarize, using `await InvokeAsync(StateHasChanged)` is the correct approach in Blazor WebAssembly when you need to invoke the `StateHasChanged` method to trigger a re-render of the component. It ensures that the method is executed on the main thread, preventing any potential threading issues.